Problema 1C21

Distribuição eletrônica de cada átomo: $$Si:\;[Ne]\,3s^{2}\,3p^2$$ $$Cl:\;[Ne]\,3s^2\,3p^{5}$$ $$Rb:\;[Kr]\,5s^{1}$$ $$Ti:\;[Ar]\,4s^{2}\,3d^{2}$$ $$Cr:\;[Ar]\,4s^{1}\,3d^{5}$$ Cálculo dos números quânticos: $Si: 3p^{2}$ $$\underset{-1}{\boxed{\uparrow\;\;}}\underset{0}{\color{red}\boxed{\uparrow\;\;}}\underset{1}{\boxed{\phantom\uparrow\;\; }}$$ $$n=3\;;\;l=1\;;\;m_{l}=0$$ $Cl:3p^{5}$ $$\underset{-1}{\boxed{\uparrow\downarrow}}\underset{0}{\color{red}\boxed{\uparrow\downarrow}}\underset{1}{\boxed{\uparrow\;\; }}$$ $$n=3\;;\;l=1\;;\;m_{l}=0$$ $Rb: 5s^{1}$ $$\underset{0}{\color{red}\boxed{\uparrow\;\;}}$$ $$n=5\;;\;l=0\;;\;m_{l}=0$$ $Ti:3d^{2}$ $$\underset{-2}{\boxed{\uparrow\phantom\downarrow}}\underset{-1}{\color{red}\boxed{\uparrow\phantom\downarrow}}\underset{0}{\boxed{\phantom\uparrow\phantom\downarrow}}\underset{1}{\boxed{{\phantom\uparrow\;\;}}}\underset{2}{\boxed{{\phantom\uparrow{\;\;}}}}$$ $$n=3\;;\;l=2\;;\;m_{l}=-1$$ $Cr:3d^{5}$ $$\underset{-2}{\boxed{\uparrow\phantom\downarrow}}\underset{-1}{\boxed{\uparrow\phantom\downarrow}}\underset{0}{\boxed{\uparrow\phantom\downarrow}}\underset{1}{\boxed{{\uparrow\phantom\downarrow}}}\underset{2}{\color{red}\boxed{{\uparrow{\phantom\downarrow}}}}$$ $$n=3\;;\;l=2\;;\;m_{l}=2$$