Problema 2A17

Cálculo da massa molar de hexafluoreto de urânio: $$M_{\ce{UF6}}=M_{\ce{U}}+6\cdot M_{\ce{F}}$$ $$M_{\ce{UF6}}=238+6\cdot19=\pu{352 g mol-1}$$ Cálculo do número de mols de hexafluoreto de urânio: $$n=\frac{m}{M}$$ $$n=\frac{\pu{25000 g}}{\pu{352 g mol-1}}$$ $${n_\ce{UF6}=\pu{71 mol}}$$ Pela estequiometria do composto: $$\frac{n_{\ce{F}}}{6}=\frac{n_{\ce{UF6}}}{1}$$ $$\frac{n_{\ce{F}}}{6}=\frac{71}{1}$$ $$\boxed{n_{\ce{F}}=\pu{426 mol}}$$